Coulombs to Milliampere-hours
1 Coulomb equals 0.277778 Milliampere-hours using exact coulomb-based electric charge definitions.
Direct Answer
1 Coulomb equals 0.277778 Milliampere-hours
This conversion uses exact coulomb-based electric charge definitions.
For 0.001 Coulombs, the result equals 0.000278 Milliampere-hours.
Converter Calculator
0.277778 Milliampere-hours (mAh)
SwitchExplanation
Formula: Milliampere-hours = Coulombs × 0.277778. Why: ampere-hour units convert to charge through current over time, with 1 Ah = 3600 C exactly and 1 mAh = 3.6 C exactly, while coulomb-prefixed units scale by exact powers of ten.
Coulombs (C): the SI unit of electric charge, defined by the exact current-time relationship 1 C = 1 A·s.
Milliampere-hours (mAh): a battery-scale electric-charge unit equal to one thousandth of an ampere-hour, commonly used for small batteries and portable electronics.
This route is mainly useful when switching between battery-capacity style units and standard SI charge units while keeping the same physical quantity.
This conversion is purely multiplicative with no offset because both units reduce exactly to coulombs under the same electric-charge model.
Common Conversion Values
| Coulombs (C) | Milliampere-hours (mAh) |
|---|---|
| 0.001 | 0.000278 |
| 0.01 | 0.002778 |
| 0.1 | 0.027778 |
| 1 | 0.277778 |
| 10 | 2.777778 |
| 100 | 27.777778 |
| 1,000 | 277.777778 |
| 5,000 | 1,388.888889 |
Frequently Asked Questions
What is 1 coulomb in milliampere-hours?
1 Coulomb equals 0.277778 Milliampere-hours on this page.
Does this Coulombs to Milliampere-hours page use 1 Ah = 3600 C?
Yes. Routes that involve ampere-hours convert through the exact current-time relationship 1 Ah = 3600 C, then apply any needed SI prefix scaling.
When would I convert coulombs to milliampere-hours?
This route is mainly useful when switching between battery-capacity style units and standard SI charge units while keeping the same physical quantity.
How do I reverse Coulombs to Milliampere-hours?
Use the mirror Milliampere-hours to Coulombs route; it applies the inverse relationship with the same electric-charge assumptions.