Black Rum Cups to Grams
1 US cup of Black Rum is about 225.47 grams using the density reference for this converter.
Direct Answer
1 US cup of Black Rum equals 225.47 g
grams = cups × 225.47
2 cups = 450.94 g
This uses Black Rum at 40% ABV (not pure ethanol), so density differs from alcohol-only references.
Converter Calculator
Explanation
Convert US cups of black rum to grams using a density reference of 0.953 g/mL. With the US cup fixed at 236.588 mL, that gives 225.47 grams per cup for this ingredient.
That is especially useful for cocktail specs, batching sheets, and inventory work where black rum starts from weight but service still uses poured measures. Black Rum is treated here as 40% ABV, so stronger or lower-proof bottles can shift the practical density slightly.
Common Conversion Values
| Cups | Grams |
|---|---|
| 1/4 | 56.37 |
| 1/3 | 75.15 |
| 1/2 | 112.73 |
| 3/4 | 169.1 |
| 1 | 225.47 |
| 1 1/2 | 338.2 |
| 2 | 450.94 |
| 3 | 676.41 |
| 4 | 901.87 |
Frequently Asked Questions
How many grams are in 1 cup of Black Rum?
1 US cup of Black Rum is 225.47 grams using the density reference for this converter.
What density basis does this cup conversion use for Black Rum?
It uses a density of 0.953 g/mL with the US cup standard (236.588 mL).
How many grams are in 2 cups of Black Rum?
2 US cups of Black Rum are 450.94 grams using the density reference for this converter.
How do I convert Black Rum grams back to cups?
Use the mirror Grams To Cups page; for this ingredient, 1 g = < 0.01 cups.