Gin (40% ABV) Grams to Milliliters
1 gram of Gin (40% ABV) is about 1.05 milliliters with the density used here.
Direct Answer
1 g of Gin (40% ABV) equals 1.05 mL
milliliters = grams ÷ 0.952
250 g = 262.605 mL
This uses Gin (40% ABV) at 40% ABV (not pure ethanol), so density differs from alcohol-only references.
Converter Calculator
1.05 Milliliters
SwitchExplanation
Convert grams of gin (40% abv) into milliliters using the same 0.952 g/mL density reference used on the reverse page.
That is especially useful for cocktail specs, batching sheets, and inventory work where gin (40% abv) starts from weight but service still uses poured measures. Gin (40% ABV) is treated here as 40% ABV, so stronger or lower-proof bottles can shift the practical density slightly.
Common Conversion Values
| Grams | Milliliters |
|---|---|
| 25 | 26.261 |
| 50 | 52.521 |
| 75 | 78.782 |
| 100 | 105.042 |
| 150 | 157.563 |
| 200 | 210.084 |
| 250 | 262.605 |
| 500 | 525.21 |
Frequently Asked Questions
How many milliliters is 1 gram of Gin (40% ABV)?
1 gram of Gin (40% ABV) is 1.05 milliliters with the density used here.
What density basis is used for Gin (40% ABV)?
It uses a density of 0.952 g/mL for Gin (40% ABV).
How many milliliters is 250 g of Gin (40% ABV)?
250 g of Gin (40% ABV) is 262.605 milliliters with the density used here.
How do I convert Gin (40% ABV) milliliters back to grams?
Use the mirror Milliliters To Grams page; for this ingredient, 1 mL = 0.952 g.